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Aneli [31]
3 years ago
8

The chess club members bought 6 tickets to a tournament for $15.How much would they have paid if all 9 members wanted to go? Sho

w your work.
Mathematics
2 answers:
Kitty [74]3 years ago
8 0
First, you would do 15 divided by 6, since you want to find out how much one ticket costs. 15 <span>÷ 6 = 2.5. So, each ticket costs $2.5. Now, you would multiple 2.5 by 9. 2.5 x 9 = 22.5. The chess club members would have to pay $22.50 if all 9 members wanted to go to the tournament.</span>
Ludmilka [50]3 years ago
4 0
$22.50 is your awnser hope i helped oh btw search up unit rates it should help<span />
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22% of the customers visiting the suit department of a certain store will purchase a suit, 30% will purchase a shirt and 28% wil
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Answer:

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Step-by-step explanation:

A The event that a persons buys a suit  

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P(AB)= 11%

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P(BC)= 10%

P(ABC)= 6%

A u B u C Is the event that any item is bougth

AC u AC u BC Is the event that any two events occured

So the wanted probability is

P[(A u B u C )(AB u AC u BC)^c

P[(A u B u C )=P(AB)+ P(BC)+P(BC)

P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06

                      =0,51

0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c

        =0,28

1000 CUSTOMERS*28%=280

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