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Aneli [31]
3 years ago
8

The chess club members bought 6 tickets to a tournament for $15.How much would they have paid if all 9 members wanted to go? Sho

w your work.
Mathematics
2 answers:
Kitty [74]3 years ago
8 0
First, you would do 15 divided by 6, since you want to find out how much one ticket costs. 15 <span>÷ 6 = 2.5. So, each ticket costs $2.5. Now, you would multiple 2.5 by 9. 2.5 x 9 = 22.5. The chess club members would have to pay $22.50 if all 9 members wanted to go to the tournament.</span>
Ludmilka [50]3 years ago
4 0
$22.50 is your awnser hope i helped oh btw search up unit rates it should help<span />
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vfiekz [6]

Answer:

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Step-by-step explanation:

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3 years ago
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Margarita [4]

Answer:

A, C, F

Step-by-step explanation:

Definition: The circumcenter is  the center of the triangle's circumcircle - the circle that passes through all three of the triangle's vertices. If point H is the circumcenter of the triangle DEF, then the circumcircle passes through its vertices D, E and F (option A is true).

Option B is false, the circumcircle doesn't pass through the points L, M and N. This option is true for inscribed circle, not for circumcircle.

Option C is true, because HD and HE are the radii of the circumcircle.

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3 years ago
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olchik [2.2K]
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3 years ago
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kirill [66]
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Read 2 more answers
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iVinArrow [24]

Answer: (a)

Step-by-step explanation:

Suppose the original function is y=\left | x \right |

To shift it 2 units right, replace x by x-2 such that

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So, the function becomes y=\left | x -2\right |

4 0
3 years ago
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