AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
Answer:
112.36 yd^2
Step-by-step explanation:
10.6 * 10.6 = 112.36
Answer: 1/3
Explanation:
1/12 of the squad are suspended:
1/12 x 24 = 24/12 = 2
So 2 player are suspended
24 - 2 = 22 player
And some are injured leaving 14 left to play:
22 - 14 = 8 players injured
So 8/24 is the fraction of injured player.
But 8/24 = 1/3 so we can say 1/3 of the whole squad are injured.
<h3>
Answer: y = 3x+18</h3>
Slope = 3
Y intercept = 18
==================================================
Work Shown:
m = slope
m = (y2-y1)/(x2-x1)
m = (0-(-9))/(-6-(-9))
m = (0+9)/(-6+9)
m = 9/3
m = 3 ... is the slope
-------
y = mx+b
y = 3x+b .... plug in the slope
-9 = 3(-9)+b ... plug in the point (x,y) = (-9,-9)
-9 = -27+b
-9+27 = -27+b+27 .... adding 27 to both sides
18 = b
b = 18 ... is the y intercept
---------
We found that m = 3 is the slope and b = 18 is the y intercept
y = mx+b turns into y = 3x+18
Probalbity is (desired outcomes)/(total possible outcomes)
total possible=200
desired outcomes=4 tickest (he wants his tickets to be chosen)
prob=4/200=2/100=1/50
probablity is 1/50 or 0.02