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posledela
3 years ago
13

a plumber is hired to stop leaks in a bathroom the faucet drips every six seconds the shower drips every 9 seconds if both fixtu

res just dripped how long will it be before they both die at the same time again explain your work
Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

Answer:

18

Step-by-step explanation:

The LCD of 6 and 9 is 18.

6: 6, 12, 18

9: 9, 18

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If 18-6x is 4 less than -8, what is the value of -3x?
UNO [17]

Answer:

-15

Step-by-step explanation:

x=5

4 0
3 years ago
Read 2 more answers
4+4+8+8+422+33+65520222222+222
Nitella [24]

Answer:

4+4+8+8+422+33+65520222222+222= 65,520,222,923

4 0
3 years ago
Matthew made slightly larger blanket that was 8 Ft long. Its area is 64 sq ft what is its perimeter?
Andreas93 [3]

Answer:

32 ft

Step-by-step explanation:

Given data

Length= 8ft

Area= 64 f^2

Let us find the width

Area= Length*Width

64= 8* Width

Width= 64/8

Width= 8ft

Hence the perimeter= 2L+2W

P= 2*8+2*8

P= 16+16

P= 32 ft

5 0
2 years ago
I REALLY NEED HELP!!!<br> 5^-3=
stiv31 [10]
1/125 or 0.008
fraction or decimal
3 0
2 years ago
Read 2 more answers
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
2 years ago
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