Ask question

Ask question

All categories

3 years ago

12

The ratio of the weight of an object on Planet A to the weight of the same object on Planet B is 100 to 3. If an elephant weighs

3800 pounds on Planet A, find the elephants weight on Planet B

2 answers:

Crank3 years ago

7 0

This problem can be solved using ratios:

$100:3 = 3800:x$

Now we solve for x by doing the following algebra:

$3800*3 = 100x$

$11400 = 100x$

$114 = x$

The answer is 114 pounds

olganol [36]3 years ago

3 0

Answer:

the elephants weight on Planet B is 114.first you divide 3800 by 100 it gives you 38 then multiply 38 times 3 it gives you 114.the answer of the question is 114. you have to use unit rate or the whole enchilada method.

Step-by-step explanation:

You might be interested in

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago

Multiply and simplify. (x + 3)(x - 8)

Kazeer [188]

Answer:

$x^{2} - 5x - 24$

Step-by-step explanation:

( x + 3 )( x - 8 ) =

$x^{2}$ - 8x + 3x - 24 = $x^{2}$ - 5x -24

4 0

3 years ago

If 1 1/2 sections are 3/4 mile long, how long is each section?

nydimaria [60]

Answer:

1/2 mile

Step-by-step explanation:

.75 mile /1.5 sections = .5 mile/section

6 0

2 years ago

The glee club has a set of 48 classical CDs and a set of 42 show tunes CDs each second be divided equally among the club members

Nata [24]

The glee club could have 6 members so the 48 classical CDs would be divided into 8 and the 42 show tunes could be divided into 7

4 0

3 years ago

What is the length of a rectangle with an area of 48 yd squared, and a width of 3 yd

Leona [35]

The length of the rectangle is 16.

7 0

3 years ago

Read 2 more answers