Answer:
The answer is below
Step-by-step explanation:
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?
Solution:
Let the width of the box be x cm.
The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40
The height of the box = 12 cm
The volume of the box can be gotten from the formula:
Volume = length × width × height
Substituting:
Volume = (x + 40) × (x) × 12
Volume = 12x(x + 40)
Therefore the volume of the new box is 12x(x + 40)
Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
If a 12 oz bottle of shampoo lasted for 16 weeks, we have a ratio of 12:16 which can be shortened to 3:4.
Now if we have 18 oz bottle we know that it's 1/2 more than 12 oz bottle, so the ratio will be also 1/2 more. So if it was 12:16, the new ratio will be:
12 + (1/2 * 12) : 16 + (1/2 * 16)
12 + 6 : 16 + 8
18 : 24
It means that 18 oz bottle should last for 24 weeks. Of course the ratio has to stay the same in its lowest form in both situations and as 18:24 can be shortened to 3:4, it proves it's correct :)
I'm assuming this is a system of equations you want solved so,
x = -y + 3
-2(-y+3)+4y = 6
2y - 6 + 4y = 6
6y = 12
y = 2
x + 2 = 3
x = -1
(-1,2)
