The answer would be 6fg^3+5f^2g^2+f^3g-7
Answer:
A not rational number is called a irrational number btw. Anyway Some examples are √2 and pi.
Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
Multiply the equations by 2 and then subtitude,
True they could be congruent by ASA