Please help me solve 9 and 10 ASAP please

Solve the following system of equations algebraically:

d1i1m1o1n [39]

Answer:

(2,1) , (-4,-17)

x = 2 , y = 1

x = − 4 , y = − 17

5 0

3 years ago

James states that quadrilateral

mr_godi [17]

Using the distance formula,

$AD=\sqrt{(-1-3)^{2}+(-3-(-4))^{2}}=\sqrt{17}\\\\BC=\sqrt{(5-9)^{2}+(1-0)^{2}}=\sqrt{17} \\\\\therefore \overline{AD} \cong \overline{BC}$

$AB=\sqrt{(-1-5)^{2}+(-3-1)^{2}}=\sqrt{52}=2\sqrt{13}\\\\CD=\sqrt{(9-3)^{2}+(0-(-4))^{2}}=\sqrt{52}=2\sqrt{13}\\\\\therefore \overline{AB} \cong \overline{CD}$

Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.

3 0

2 years ago

A point located at (4, 7) is translated up 5 units. What are the coordinates of the image?

Fantom [35]

Can u make a graaph showing this

7 0

4 years ago

jacob just had lunch at a restaurant and leaves a 18% tip. Choose all the expressions that will give his total cost in terms of

Leokris [45]

Answer:

1.18b

Step-by-step explanation:

Jacob had lunch at a restaurant and his bill was b.

Now, Jacob leaves 18% of his bill amount as a tip.

So, the tip amount at the rate of 18% of the bill amount will be $\frac{18 \times b}{100} =0.18 \times b$

Therefore, the total cost of Jacob for the lunch will be b + 0.18b = 1.18b. (Answer)

8 0

3 years ago

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0

1 year ago