Step-by-step explanation:
answer is 22 students in the team
<em>how </em><em>do </em><em>u </em><em>get </em><em>it? </em>
you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22
Answer:
0.06
Step-by-step explanation:
A b and c are your variables
Hope this helps
Answer:
18.67% probability that the sample proportion does not exceed 0.1
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For the sampling distribution of a sample proportion, we have that 
In this problem, we have that:

What is the probability that the sample proportion does not exceed 0.1
This is the pvalue of Z when X = 0.1. So



has a pvalue of 0.1867
18.67% probability that the sample proportion does not exceed 0.1
B 6x - 3
help theres a character limit