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PIT_PIT [208]
3 years ago
11

X-1/x-1=1 what is the answer????

Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Answer:

0

Step-by-step explanation:

×-1/×-1=1

×-1=1(×-1)

×-1=×-1

×-×=-1+1

0=0

0

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Please help.. I will give points
Daniel [21]

A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.

B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.

C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.

D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.

Your answers are A and B.

I hope this helps ;)

4 0
3 years ago
Read 2 more answers
Use a translation rule to describe the translation of ABC that is 6 units to the right and 10 units down.​
vesna_86 [32]

Answer:

(x, y ) → (x + 6, y - 10 )

Step-by-step explanation:

6 units right is + 6 in the x- direction

10 units down is - 10 in the y- direction

the translation rule is

(x, y ) → (x + 6, y - 10 )

6 0
3 years ago
Help plz I really need it
makvit [3.9K]

Answer:

translation then reflection

Step-by-step explanation:

5 0
3 years ago
What is the answer help ASAP!! :))
vampirchik [111]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
The base of a solid is bounded by the curve y = sqrt (x+1) the x-axis and the line x = 1. the cross sections, taken perpendicula
Andrei [34K]

See attached for a sketch of some of the cross sections.

Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).

If the thickness of each cross section is ∆x, then the volume of each cross section is

∆V = (√(x + 1))² ∆x = (x + 1) ∆x

As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

\displaystyle \int_{-1}^1 (x+1) \, dx = \left(\frac{x^2}2 + x\right) \bigg|_{-1}^1 = \boxed{2} ~~~~ (B)

3 0
2 years ago
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