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3 years ago

A circle has a radius of 6 in.

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

The answer is 1.5 in.

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Find the domain of the graphed function!

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

you can see that the graph only extends from 2 to 5, and because of the closed circles you know its ≤ not < for the signs

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2 years ago

Joanie wrote a letter that was 1 1/4 pages long. Katie wrote a letter that was 3/4 page shorter than Joanie's letter. How long w

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The answer to your question is 2/4 which is 1/2

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2 years ago

In general, the value measured by the horizontal axis is called the ________<br> variable.

bixtya [17]

Answer:

independent

Step-by-step explanation:

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3 years ago

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Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

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3 years ago

Use the graph to answer the question.

stealth61 [152]

A 180 counterclockwise rotation about the origin followed by a reflection of the y-axis

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2 years ago

Read 2 more answers