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Margarita [4]
3 years ago
5

Juations

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

John = 9

Kim = 6

Vanessa = 3

Step-by-step explanation:

John = n

Kim = n - 3

Vanessa = 0.5n - 1.5

Add them:

2.5n - 4.5 = 18

2.5n = 22.5

n = 9

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The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
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5 1/2 is how many half cups?
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11 cups is how many 5 and a half cups is in half cups
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What is y=3/8x-5<br> in a table of values
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jeka57 [31]
Q1: 7×6 = 42
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Q4: 4(5/2)^2 = 4×5/2×5/2 = 4×25/4 = 25 in^3
Q5: 3(13/2)(3/2) = 117/4 = 29.25 (29 1/4) in^3
Q6: (0.9)^3 = 0.729 cm^3
6 0
3 years ago
How do i show proof?​
Alexus [3.1K]

Answer:

Step-by-step explanation:

If m is parallel to p then the angles 1 and 8 are =. If 8 and 2 are = (as said in the paper), then a and b are parallel

8 0
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