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Scilla [17]
3 years ago
13

A printing company’s costs for printing a book are $500 for labor and running the necessary machinery plus $3 per book printed.

The total cost for printing a particular book must be less than $1,300.
a. (MGSE9-12.A.CED.1) Write an inequality to represent this situation. Let n represent the number of books printed.

b. (MGSE9-12.A.REI.3) Solve your inequality for n. What is the greatest number of books that can be printed? Show your work.
Mathematics
2 answers:
dybincka [34]3 years ago
5 0
C
500+3n
3n
n
Max books = 266 for a total cost of $1298
Anika [276]3 years ago
4 0

Answer:

A. 500 + n 3 < 1300

B. 266

Step-by-step explanation:

500 dollars por labor and running and 3 more dolars every book the make should be less than 1300$

500 + n 3 < 1300

n 3 < 1300 - 500

n < 800 / 3

n < 266,667

As books are units and should be natural numbers, then the gratest number of books is 266.

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Evaluate [3+(8-2)]x5
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Answer:

45

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Subtract the numbers

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How do you Solve d+7/−3=4?
vova2212 [387]

Answer:

One solution was found :

                  d = 19/3 = 6.333

Step-by-step explanation:

Step by step solution :

Step  1  :

            7

Simplify   ——

           -3

Equation at the end of step  1  :

        7    

 (d +  ——) -  4  = 0

       -3    

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  -3  as the denominator :

         d     d • -3

    d =  —  =  ——————

         1       -3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

d • 3 + 7 • -1     3d - 7

——————————————  =  ——————

      3              3  

Equation at the end of step  2  :

 (3d - 7)    

 ———————— -  4  = 0

    3        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        4     4 • 3

   4 =  —  =  —————

        1       3  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(3d-7) - (4 • 3)     3d - 19

————————————————  =  ———————

       3                3  

Equation at the end of step  3  :

 3d - 19

 ———————  = 0

    3  

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 3d-19

 ————— • 3 = 0 • 3

   3  

Now, on the left hand side, the  3  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  3d-19  = 0

Solving a Single Variable Equation :

4.2      Solve  :    3d-19 = 0

Add  19  to both sides of the equation :

                     3d = 19

Divide both sides of the equation by 3:

                    d = 19/3 = 6.333

One solution was found :

                  d = 19/3 = 6.333

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