Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.
Anyway, it means that the area is given by
![A = \cfrac{\overline{AB}\times\overline{AC}}{2}](https://tex.z-dn.net/?f=%20A%20%3D%20%5Ccfrac%7B%5Coverline%7BAB%7D%5Ctimes%5Coverline%7BAC%7D%7D%7B2%7D%20)
Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:
![\overline{AB} = |2-0| = |2| = 2](https://tex.z-dn.net/?f=%20%5Coverline%7BAB%7D%20%3D%20%7C2-0%7C%20%3D%20%7C2%7C%20%3D%202%20)
The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:
![\overline{AC} = |4-0| = |4| = 4](https://tex.z-dn.net/?f=%20%5Coverline%7BAC%7D%20%3D%20%7C4-0%7C%20%3D%20%7C4%7C%20%3D%204%20)
So, the area is
![A = \cfrac{2\times 4}{2} = 4](https://tex.z-dn.net/?f=%20A%20%3D%20%5Ccfrac%7B2%5Ctimes%204%7D%7B2%7D%20%3D%204)
The length of AC is congruent to WY
d = 10
The population in 1992 was 83 mill....population is 1996 was 88 mill...
so in 4 years (from 1992 to 1996), the population rose by (88 mill - 83 mill) = 5 mill
Thats 5,000,000 / 4 = 1,250,000 per year.
so in 2013 (17 years from 1996), the population would be :
83 mill + 1,250,000(17) = 83 mill + 2,125,000 = 85,125,000 <==
Answer:
35.0 units
Step-by-step explanation:
we know that
A <u><em>mid-segment</em></u> of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment is always parallel to the third side, and the length of the mid-segment is half the length of the third side
so
![6x+5=\frac{1}{2}(3x+55)](https://tex.z-dn.net/?f=6x%2B5%3D%5Cfrac%7B1%7D%7B2%7D%283x%2B55%29)
solve for x
![12x+10=3x+55\\12x-3x=55-10\\9x=45\\x=5](https://tex.z-dn.net/?f=12x%2B10%3D3x%2B55%5C%5C12x-3x%3D55-10%5C%5C9x%3D45%5C%5Cx%3D5)
Find the length of the mid-segment
substitute the value of x
![6(5)+5=35.0\ units](https://tex.z-dn.net/?f=6%285%29%2B5%3D35.0%5C%20units)