The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units.What is BC, the height of the
pyramid?
2 answers:
The picture in the attached figure
we know that
<span>The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units
so
AC=CD=AD=14 units
in the right triangle ABC
tan A=opposite side angle A/adjacent side angle A
opposite side angle A=BC
adjacent side angle A=AC
angle A=45 degrees
so
tan 45=BC/14------------> BC=14*tan 45-------> BC=14*1-----> BC=14 units
the answer is
</span><span>the height of the pyramid is 14 units (BC)</span>
we know that
<span>The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units
so
AC=CD=AD=14 units
in the right triangle ABC
tan A=opposite side angle A/adjacent side angle A
opposite side angle A=BC
adjacent side angle A=AC
angle A=45 degrees
so
tan 45=BC/14------------> BC=14*tan 45-------> BC=14*1-----> BC=14 units
the answer is
</span><span>the height of the pyramid is 14 units (BC)</span>
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