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Sonbull [250]
3 years ago
8

What is the slope of line P / answers: -3, 1.5, 3

Mathematics
2 answers:
inysia [295]3 years ago
6 0
P= -3 =m
Q= 3 =m
so slope is rise/run
the only diff is that one is negative and one is positive.
in slope. there are four directions. Up, Down, Left, and Right
U/R and D/L are positive slopes.
U/L and D/R are negatives slopes.
stepladder [879]3 years ago
4 0
The slope of p is 3
the slope of q is -3
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In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. if there were 45 basket
IgorLugansk [536]
Let
 x: number of regular basketball
 y: number of long-distance basket
 We have the following system of equations:
 2x + 3y = 96
 x + y = 45
 Solving the system we have
 y = 45-x
 2x + 3 (45-x) = 96
 2x +135 -3x = 96
 -x = 96 -135
 x = 39
 Then,
 y = 45-x
 y = 45-39
 y = 6
 answer
 were made
 regular baskets = 39
 long-distance baskets = 6
3 0
3 years ago
What is the decimal value of the fraction 2/7 ? 0.285714¯ 0.285714¯¯¯¯¯¯¯¯¯¯ 0.2857142857¯¯¯¯¯ 0.285714
Leviafan [203]
The decimal of the fraction 2/7 is 0.2857142857
4 0
3 years ago
Read 2 more answers
Whats the square root of 33
photoshop1234 [79]

Answer:

The square root of 33 is 5.74456264654

3 0
2 years ago
Read 2 more answers
SOMEONE HELP ME PLEASE
IgorC [24]

A standard die has numbers = 1,2,3,4,5 and 6

Total outcomes = 6

P = Number of outcomes/Total Outcomes

Even and less than 4 = 1,2,3,4 and 6

P = 5/6

Answered by GauthMath if you like please click thanks and comment thanks

3 0
2 years ago
f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many
Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming that the proportion is estimated \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849  

And rounded up we have that n=1849

7 0
2 years ago
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