The volume of a rectangular prism varies jointly with the length and width of the figure when the height remains constant. The v
2 answers:
Answer:
The correct option is 1.
Step-by-step explanation:
The volume of a rectangular prism varies jointly with the length and width of the figure when the height remains constant.
Let the height of both rectangular prism be h cm.
The volume of a prism is
Where, l is length, b is breadth or width and h is height.
The volume of a rectangular prism is 672 cubic centimeters. The figure has a length of 8 centimeters and a width of 14 centimeters.
Divide both sides by 112.
The value of h is 6 cm. It means the height of both prism is 6 cm.
A second prism has a length of 12 centimeters and a width of 8 centimeters. So, the volume of second prism is
The volume of second prism is 576 cubic centimeters. Therefore the correct option is 1.
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Answer:
b) 2.00
Step-by-step explanation:
For each name, there are only two possible outcomes. Either it is authentic, or it is not. The probability of a name being authentic is independent of any other name. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
She randomly selects five names from the list for validation.
This means that
40% of the names on the list are non-authentic
This means that
The expected (average) value of x is
The correct answer is given by option B.
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
Area of region 2 = ar(DHBC)
Area of region 3 = ar(GFEH)
Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
