7b + 3 - 4b = 3 - 3(b + 4)
3b + 3 = 3 - 3b - 12
3b + 3b = 3 - 12 - 3 = -12
6b = -12
b = -12/6 = -2
b = -2
First find the new coordinates for P and Q after the translations:
P'(2 + 3, 4 - 4) = P'(5, 0)
Q'(-3 + 3, 2 - 4) = Q'(0, -2)
Now, find the slope from this:
(0 - (-2))/(5 - 0) = 2/5
The slope has remained the same. It is important to note that after any translation, the slope will always remain the same. However, this is not always so for rotations and reflections.
To solve the question we use the compound interest formula which is given by:
A=p(1+r)^(nt)
where:
A=future value
p=principle
r=rate
n=number of terms
t=time
thus plugging in the values in the formula we shall have:
A=835(1+0.04)^(4t)
simplifying this we get the sequence:
A=835(1.040)^(4t)
Thus the answer to the sequence will be:
A=835(1.040)^(4t)
