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AleksAgata [21]

3 years ago

5

Jen worked eight weeks as a lifeguard. She was able to save $336. She owns the same amount each week. Write an equation where W=

equals weeks to represent the situation. Solve the equation

1 answer:

Juli2301 [7.4K]3 years ago

5 0

Answer: 1(w)=$336

Step-by-step explanation:

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AlladinOne [14]

Answer:

2

Step-by-step explanation:

2^{4-3}

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4 years ago

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The wheel on a car completes

mars1129 [50]

Answer:

Step-by-step explanation:

Let d be the diameter of the wheel.

Circumference = πd

(35.325 m)/(25 revolutions) = (1.413 m)/revolution

πd = 1.413

d = 1.413/π = 0.45 m

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3 years ago

Y = -4x + 8<br> Y=3/5x - 6/5

VladimirAG [237]

Answer:

x=2 and y=0

Step-by-step explanation:

Rewrite equations:

y=−4x+8;y=

3

5

x+

−6

5

Step: Solvey=−4x+8for y:

y=−4x+8

Step: Substitute−4x+8foryiny=

3

5

x+

−6

5

:

y=

3

5

x+

−6

5

−4x+8=

3

5

x+

−6

5

−4x+8+

−3

5

x=

3

5

x+

−6

5

+

−3

5

x(Add (-3)/5x to both sides)

−23

5

x+8=

−6

5

−23

5

x+8+−8=

−6

5

+−8(Add -8 to both sides)

−23

5

x=

−46

5

−23

5

x

−23

5

=

−46

5

−23

5

(Divide both sides by (-23)/5)

x=2

Step: Substitute2forxiny=−4x+8:

y=−4x+8

y=(−4)(2)+8

y=0(Simplify both sides of the equation)

5 0

3 years ago

A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?

GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

$240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)$

$480=\left(2x+1\right)\left(6x-3\right)$

$480=12x^2-3$

Subtract 480 from both sides

$12x^2-3-480=480-480$

$12x^2-483=0$

$3\left(4x^2-161\right)=0$

$3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0$

solving

$2x+\sqrt{161}=0$

$2x=-\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{-\sqrt{161}}{2}$

$x=-\frac{\sqrt{161}}{2}$

also solving

$2x-\sqrt{161}=0$

$2x=\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{\sqrt{161}}{2}$

$x=\frac{\sqrt{161}}{2}$

Therefore, the values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

3 0

3 years ago

Use long or synthetic division to find the following quotients <br>(x^3+2x^2!22x-45)÷(x+5)

svetoff [14.1K]

Answer:

$\boxed{\textsf{ The quotient is $\sf x^2-3x-7$ and the remainder is (-10).}}$

Step-by-step explanation:

Here we will be using long division method to find the quotient . Here we need to divide (x³+2x²-22x-45) and (x+5) . So lets divide .

x+5) x³+2x²-22x-45 ( x² -3x -7

x³ + 5x²

- -

______________

- 3x²-22x -45

-3x² -15x

+ +

______________

-7x -45

-7x -35

______________

-10

<u>Quotient</u><u> </u>= x² -3x -7

<u>Remainder </u>= (-10)

<h3><u>★</u><u>Hence </u><u>the</u><u> </u><u>quotient</u><u> </u><u>is </u><u>x²</u><u> </u><u>-3x </u><u>-</u><u>7</u><u> </u><u>and </u><u>the</u><u> </u><u>remainder</u><u> </u><u>is </u><u>(</u><u>-</u><u>1</u><u>0</u><u>)</u><u> </u><u>.</u></h3>

7 0

3 years ago