Combining like terms with a rational coefficients <br> 1.) 3.7x+7.2-2.2x ? <br> 2.) 6.1x-7-8.2x ?

Find the volume of the cubes or rectangular prisms in cubic centimeters.

DanielleElmas [232]

a) Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

b) Volume of cube is $\frac{8}{125}\,\,cm^3$

c) Volume of cube is $\frac{1}{125}\,\,cm^3$

d) Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Step-by-step explanation:

Part a)

Volume of rectangular prism with

length= $\frac{3}{5}\,\,cm$

width= $\frac{4}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{3}{5} *\frac{4}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{36}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

Part b)

Volume of cube with side length of $\frac{2}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{2}{5})^3\\ Volume\,\,of\,\,cube=\frac{8}{125}\,\,cm^3$

So, Volume of cube is $\frac{8}{125}\,\,cm^3$

Part c)

Volume of cube with side length of $\frac{1}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{1}{5})^3\\ Volume\,\,of\,\,cube=\frac{1}{125}\,\,cm^3$

So, Volume of cube is $\frac{1}{125}\,\,cm^3$

Part d)

Volume of rectangular prism with

length= $\frac{1}{5}\,\,cm$

width= $\frac{2}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{1}{5} *\frac{2}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{6}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Keywords: Volume

Learn more about Volume at:

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6 0

3 years ago

The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.Refer to

Dafna11 [192]

Given that

the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.

And we need to find What is the minimum weight of the middle 95% of the players?

Explanation -

Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.

Two standard deviations = 2 x 25 pounds = 50 pounds

So the minimum weight = 200 pounds - 50 pounds = 150 pounds

Hence the final answer is 150 pounds.

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1 year ago

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ExtremeBDS [4]

Answer:

what help you needed. ??

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3 years ago

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olganol [36]

Answer:

Step-by-step explanation:

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3 years ago

Hannah loves to shop. She can shop in 1/9 of the mall in 1/4 of an hour. If she continues at this rate, how much of the mall can

DiKsa [7]

4/9s of the mall per hour. 1/9 + 1/9 + 1/9 + 1/9

7 0

3 years ago

Combining like terms with a rational coefficients 1.) 3.7x+7.2-2.2x ? 2.) 6.1x-7-8.2x ?