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Oksi-84 [34.3K]
3 years ago
5

Please help me with this system of inequalities​!

Mathematics
1 answer:
erica [24]3 years ago
8 0
Part A: y<4x-8 is a dotted line intercepting the y-axis at -8, and increasing by a value of 4, with shading bellow the line. The Second equation (which I can't fully type out) is a solid line intercepting the y-axis at 5,decreasing by a value of -5/2, and has shading above the line.

Part B: It does not because the point (5,-8) doesn't appear where the shaded areas meet.
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What is the axis of symmetry of the function f(x)=-(x+9)(x-21)
Firlakuza [10]
Carry out the mult.:  f(x) = -[x^2 - 21x + 9x - 189] 

Combine like terms:  f(x) = -[x^2 - 12x - 189]
Eliminate the brackets [   ]:      f(x) = -x^2 + 12x + 189
Identify coefficients a, b and c:   a= -1, b=12, c=189

The equation of the axis of symmetry is    x = -b/(2a), which here equals

x = -(12)/[2(-1)], or     x = 6

This is also the x-coordinate of the vertex.  Plug x=6 into the original equation to calculate the y-coordinate.
3 0
3 years ago
Find the least common multiple of 12 and 18?
Evgesh-ka [11]
36 is the correct answer
8 0
2 years ago
Find the length of LM. Show your work.
kicyunya [14]

Answer:

<h2>20</h2>

<em>Solution</em><em>,</em>

<em><</em><em>N=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>5</em><em>3</em><em>-</em><em>4</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>8</em><em>3</em>

<h3><em>Apply </em><em>sines </em><em>rule,</em></h3>

<em>\frac{lm}{sin \: 83}  =  \frac{14}{sin44}  \\ lm =  \frac{14 \: sin \: 83}{sin \: 44}  \\ lm = 20</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

4 0
3 years ago
Read 2 more answers
16e^2-88e+121<br> pls help me
Rufina [12.5K]

Step-by-step explanation:-8.8e +122

7 0
3 years ago
Write the answer in standard form.
viktelen [127]

Answer and step-by-step explanation:

We learn that (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

So in this case, it would be:

= x^3 + (3*x^2*2) + (3*x*2^2) + 2^3

= x^3 + 6x^2 + 3x * 4 + 8

= x^3 + 6x^2 + 12x + 8

This is the standard form of the equation

Hope it help you :3

6 0
3 years ago
Read 2 more answers
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