First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
x≤9
Step-by-step explanation:
9+2x≤27
1) Subtract both sides by 9:
2x≤18
2) Divide both sides by 2:
x≤9
Answer: There is no question so I don't know how to answer your question
Step-by-step explanation:
Answer:
3.84% of months would have a maximum temperature of 34 degrees or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of months would have a maximum temperature of 34 degrees or higher?
This is 1 subtracted by the pvalue of Z when X = 34. So



has a pvalue of 0.9616
1 - 0.9616 = 0.0384
3.84% of months would have a maximum temperature of 34 degrees or higher