Answer:
y = 1/3x + 10/3
Step-by-step explanation:
→ Write gradient into format
y = 1/3x + c
→ Substitute in (5,5)
5 = 5/3 + c
→ Find c
c = 5 - 5/3 = 10/3
→ Finish off
y = 1/3x + 10/3
Answer:
31.16
Step-by-step explanation:
Perimeter of the shaded portion = Perimeter of the rectangle - Perimeter of the 2 circles
Length of rectangle = 13
Width = 2d
d is the diameter of the circle = 2(6) = 12
Perimeter of the rectangle = 2(L+W)
Perimeter of the rectangle = 2(13+12)
Perimeter of the rectangle = 2(25)
Perimeter of the rectangle = 50
Perimeter of the semi-circle = πd/2
Perimeter of the circle = 3.14(6)/2
Perimeter of the circle = 18.84/2
Perimeter of the 2 circles = 2(18.84)/2
Perimeter of the 2 circles = 18.84
Perimeter of the shaded portion = 50 - 18.84
Perimeter of the shaded portion = 31.16
Answer:
C= -5
D = 7
Step-by-step explanation:
Answer:
Step-by-step explanation:
dy/dx= -(2x+3y+1)/(3x-2y+1)
Let x= X+p. and y = Y+q. then dy/dx = dy/dX.
dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =
dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}
Now 2p+3q+1=0……………..(1)
3p-2q +1=0…………………………(2)
p/(3+2)=q/(3–2)=1/(-4–9)
Answer:
See explanation below.
Step-by-step explanation:
Assuming the distribution on the figure attached. We have a distribution skewed to the right.
We can calculate the deviation with the following table:
Class frequency(f) (Xm) Midpoint f*Xm fXm^2
50-90 28 70 1960 137200
90-130 32 110 3520 387200
130-170 18 150 2700 405000
170-210 8 190 1520 288800
210-250 8 230 1840 423200
290-330 2 310 620 192200
410-450 2 430 860 369800
Total 98 13020 2203400
We are assuming the frequencies that;s important to mention.
We can calculate the sample variance with the following formula:
And if we replace we got:
And then the standard deviation is given bY:
So then the best answer would be : 70