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baherus [9]
3 years ago
10

3(2v-1)=6v-4 can someone pls help me with this

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

Step-by-step explanation:

dy/dx= -(2x+3y+1)/(3x-2y+1)

Let x= X+p. and y = Y+q. then dy/dx = dy/dX.

dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =

dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}

Now 2p+3q+1=0……………..(1)

3p-2q +1=0…………………………(2)

p/(3+2)=q/(3–2)=1/(-4–9)

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See the sketch of the region in the attached graph.

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\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4

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\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

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\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT

<h3>Answer: B = 2</h3>
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