3(2v-1)=6v-4 can someone pls help me with this
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The given equations are linear functions and represent straight lines.
The first equation F(x) = 2x , represent a straight line passing through the origin.
Now, we plot the rest equation using the transformation of the graph.
- If we add a constant 'a' in the function then it gets shifted upward by 'a' units.
- If we subtract a constant 'a' in the function then it gets shifted downward by 'a' units.
Using these properties, the second graph gets shifted upward by 6 units. Hence, it passes through (0,6)
Third graph will shift downward by 3 units. Hence, it passes through the point (0,-3)
Fourth graph will shift downward by 5 units. Hence, it passes through the point (0,-5)
The graph of these functions are shown in the same xy-plane in the attached file.
