Answer:
As x decreases without bound, f(x) increases without bound
As x increases without bound, f(x) approaches 0
Step-by-step explanation:
As x gets more and more negative f(x) gets bigger and bigger
f(x) = (7/10) ^ x but x is negative so flip it and then x is a larger number
(10/7) ^ large number so it will get larger
as → -∞ f(x) →∞
As x gets more and more positive f(x) gets smaller and smaller
f(x) = (7/10) ^ x closer and closer to 0. The denominator gets larger faster than the numerator = 1 / large number
as → ∞ f(x) →0
Answer:
Step-by-step explanation:
First we need to write in correct form :
We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.
So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)
Now, multiply numerator by numerator, denominator by denominator :
Step-by-step explanation:
The general equation is y = mx + c...
The given equation is 2x + y = 6
Firstly, move everything on the left except the y to the right.i.e.
y = 6 - 2x
Secondly, rearrange the values on the right to look just like the general equation.
y = -2x + 6
The equation is now in proper general form because it matches the format laid down.
Answer:
The answer is 12
Step-by-step explanation:
Multiply 1*3
Add 2 to the number
Change the first number to 5/3
Multiply 3*4
Given that triangle <span>STU
is reflected once to map onto
triangle S'T'U'.
Given that triangle STU has
vertices S(8, 6), T(2, 2), U(5, 1).
If vertex T' is at
(2, −2), this means that triangle STU is refrected across the x-axis.
A refrection across the x-axis results in an image that has the same x-value as the pre-image but a y-value that has the opposite sign of the y-value of the pre image.
Thus, a point, say (x, y), refrected over the x-axis will result in an image with coordinate (x, -y)
Therefore, given that the coordinate of S is (8, 6), then the coordinates of vertex S'</span> is (8, -6).
