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Veseljchak [2.6K]
3 years ago
8

A watch manufacturer believes that 60% of men over age 50 wear watches. So, the manufacturer took a simple random sample of 275

men over age 50 and 170 of those men wore watches. Test the watch manufacturer's claim at a=.05.
Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

the percentage of men over 50 who wear watches are 61.82%

Step-by-no step explanation:

first just multiply 275 the number of people over 5o then divide it by .6 to get 165 is the answer

i hope this is correct

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Step-by-step explanation:

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What is the slope of a line that is parallel to the line represented by the equation 3x+4y=12?
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Slope-intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

(there is probably another way to do this, but I will be doing it this way)


Isolate the "y" in the equation

3x + 4y = 12       Subtract 3x on both sides

4y = 12 - 3x        Divide 4 on both sides

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For lines to be parallel, they have to have the SAME slope. The given line's slope is -3/4, so the slope of the parallel line is also -\frac{3}{4}

8 0
3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

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Answer:

i think is is c but I not sure.

Step-by-step explanation:

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Andreyy89

Answer:

Step-by-step explanation:

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