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3 years ago

How many watts is 30 kilowatts in 24hrs

1 answer:

8 0

30,00 watts.
Think of the metric system like this: K H D B D C M
Now. you have kilo at the begining and milli at the end. To transition from left to right you multiply by 10 each time. To transition from right to left, you divide by 10 each time.

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Find A and C for both questions

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3 years ago

Write 95.417 in expanded form with multiplication

Svetllana [295]

In expanded form, it would be 9*10 + 5*1 + 4 * 0.1 + 1 * 0.01 + 7 * 0.001. Hope this helps!

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3 years ago

HELPP!! 10 points 1 question . ( explain your answer )

Greeley [361]

50.25% off because 100÷199=50.25

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3 years ago

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Suppose you buy a $50 coffee maker in an area where the sales tax is 8%. When you check out, 8% of $50 would be added to your to

ASHA 777 [7]

Answer:

Step-by-step explanation:

8% is also 8/100. This would be true for all percents 0 to 100%. If it were 42% it can be written as 42/100.

So, 8% is 8/100. If you want to find 8/100 of 50 multiply them.

8/100 * 50/1 = (8*50) /100

400/100 = 4

7 0

3 years ago

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I just need no. a please help me to prove this.

OleMash [197]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π and cos A = cos B · cos C

scratchwork:

A + B + C = π

A = π - (B + C)

cos A = cos [π - (B + C)] Apply cos

= - cos (B + C) Simplify

= -(cos B · cos C - sin B · sin C) Sum Identity

= sin B · sin C - cos B · cos C Simplify

cos B · cos C = sin B · sin C - cos B · cos C Substitution

2cos B · cos C = sin B · sin C Addition

$2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}$ Division

2 = tan B · tan C

$\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}$

<u>Proof LHS → RHS</u>

Given: A + B + C = π

Subtraction: A = π - (B + C)

Apply tan: tan A = tan(π - (B + C))

Simplify: = - tan (B + C)

$\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)$

Substitution: = -(tan B + tan C)/(1 - 2)

Simplify: = -(tan B + tan C)/-1

= tan B + tan C

LHS = RHS: tan B + tan C = tan B + tan C $\checkmark$

5 0

3 years ago