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3 years ago

What is the difference between graphing the inequality y > x + 5 and y < x + 5

Mathematics

1 answer:

Zepler [3.9K]3 years ago

4 0

Answer:

The graph on the first equation y>x+5 will be shaded above the line. The graph on the second. equation y< x+5 will be shaded below the line.

When y is less than (y<), then the graph is shaded below the line. if y is greater than,( y>) then it will be shaded above the line.

Hope this helps! Give a heart and brainlest if so!

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1.)Simplify the expression: 4 times Start Root 18 End Root plus 5 times Start Root 32 End Root

aleksley [76]

1.) 32 start root 2 end root

2.) -5 start root 5 end root

3.) 3 start root 7 end root + 7 start root 6 end root

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ehidna [41]

Answer:

121

Step-by-step explanation:

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joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each

masya89 [10]

So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
$Jeff's\ weight = 86 \frac{2}{3} \ lbs.$

Substitute again.
$x = 2(86 \frac{2}{3} )-20$

Multiply.
$x = 173 \frac{1}{3} -20$

Subtract.
$Joe's\ weight = 153 \frac{1}{3}\ lbs.$

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

$Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.$
$Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.$

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4 years ago

Suppose that the concentration (measured in gm^-3) of nitrogen in the soil along a transect in moist tundra yields data points t

kap26 [50]

Answer:

The average concentration of nitrogen in the soil along 0 ≤ x ≤ 10 is $y_{avg}=500.3 \:{\frac{g}{m^3} }$

Step-by-step explanation:

To find the average concentration between two points a and b along a transect, we measure the concentration at equal distances. Assume that f(x) is a continuous function on [a, b]. The average value of f on the interval [a, b] is

$f_{avg}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx$

To find the average concentration of nitrogen we have to take the integral over the entire range and then dividing by the distance covered in the study.

$y_{avg}=\frac{1}{10-0}\int\limits^{10}_{0} {(673.8 - 34.7x)} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\y_{avg}=\frac{1}{10-0}\int _0^{10}673.8dx-\int _0^{10}34.7xdx\\\\y_{avg}=\frac{1}{10-0}(6738-1735)\\\\y_{avg}=\frac{5003}{10}=500.3$

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4 years ago

Plsssssss help -1 3/10 + 2/5

vitfil [10]

Answer:

Step-by-step explanation:

-9/10 or -0.9

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3 years ago