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3 years ago

Choose the correct conic section to fit the equation. xy = -16

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

Answer:

Parabola

Step-by-step explanation:

none.

marin [14]3 years ago

5 0

Xy+16=0 is the answer

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Curved surface of a cone of slant height 20 cm and base radius 14 cm is ____. * 1 point 280 sq.cm 2080 sq.cm 1496 sq.cm 880 sq.c

valkas [14]

Answer:

880 cm²

Step-by-step explanation:

Given that :

Curved surface area of a cone : πrl

r = base Radius = 14 cm

l = slant height = 20 cm

Hence,

Curved surface area = π * 14 * 20

Curvwd surface are = π * 14 * 20

Curved surface area = 879.64594 cm²

Curved surface area = 880 cm²

7 0

3 years ago

I NEED HELP ASAP PLEASE AND THANK YOU What is the axis of symmetry? y= -3 (x-2) (x-4)

Lina20 [59]

The axis of symmetry is x=3

3 0

2 years ago

1. The present age of Visakha is x years. Find: I) How old was he 2 years before?

bekas [8.4K]

Answer:

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6 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Which of the following shapes are polygons with more than 444 sides?

Leviafan [203]

Hexagon and pentagon

6 0

3 years ago