Answer:
The probability that at lest one job will be missed in 57 second is
=0.819134
Step-by-step explanation:
Poisson distribution:
A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.
for x=0,1,2...
λ is the average per unit time
Given that, a job arrives at a web server with the probability 0.03.
Here λ=0.03, t=57 second.
The probability that at lest one job will be missed in 57 second is
=P(X≥1)
=1- P(X<1)
=1- P(X=0)


=0.819134
B as it goes through the correct and average amount of points on the graph, hope this helps
Good idea to look up the formula for "surface area of a sphere" and to write it down for later reference. It is A=4 pi r^2, where r is the radius of the sphere.
If the given sphere has a diameter of 7 cm, what is the radius of this sphere?
Write your answer inside the parentheses, below:
Sphere surface area = 4 pi (r)^2, or (in this case), A = 4(3.14)( )^2
48= l*w
l= 8+w
To solve for width, substitute the value of l in the first equation so that everything is in terms of w.
Final answer: 48= (8+w)*w