7. -8/3
8. 4/35
9. -21/50
10. 35/64
11.-25/54
3627 x 673:(876)= 2138290596
I got that by taking 3627x876(876) and got that
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Let's simplify step-by-step.
23
p
+
43
p
−
13
p
=
23
p
+
43
p
+
−
13
p
Combine Like Terms:
=
23
p
+
43
p
+
−
13
p
=
(
23
p
+
43
p
+
−
13
p
)
=
53
p
Answer:
The answer is both all real numbers less than 0 and all real numbers greater than 0
