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3 years ago

Jasjeet and her brother collect stamps.

Mathematics

2 answers:

Dmitrij [34]3 years ago

8 0

She had 2,500 stamps before she gave 1% to her brother, since 2,475 is 99%, i just calculated this equation: p/w = a/100

Greeley [361]3 years ago

4 0

Answer:

2500

Step-by-step explanation:

If Jasjeet gave away 1%, that means she has 99% left.

Put the 99% over 100, so you can drop the % sign.

Then you're going to cross multiply that with 2475/ ?. The ? is the unknown aka original ammount of stamps. The 2475 is the 99% of stamps she still has.

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Find the value of w<br> A. 141<br> B. 110<br> C. 80<br> D. 100

saw5 [17]

Answer:

141

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

We know z+70 = 180 since they form a straight line

z = 110

z = 1/2 ( 79+w)

110 = 1/2 ( 79+w)

220 = 79+w

220-79 = w

141 =w

5 0

2 years ago

14x + 54 = 11x + 96 x=

jenyasd209 [6]

Move the 11x to the left and the +54 to the right. Their signs will flip:

14x-11x = 96-54
3x = 42
x = 14

4 0

3 years ago

Read 2 more answers

Problem #1 HELP SHOW WORK PLS

OLEGan [10]

Answer: 30 degrees

Step-by-step explanation:

Corresponding angles of similar triangles are congruent.

5 0

1 year ago

Use the graph to state the solution for the system.

Alenkasestr [34]

Your answer would be (3,0)

4 0

3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

3 years ago