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Bond [772]
3 years ago
15

Wh8ch equation represents a linear function: A, y=2x^+1 B, y^=3x+1 C, y=5x-1 D y=4x^^-1

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0
C is your answer since it is the only one without any exponents
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Explain two methods for solving an equation. Give an example.
svlad2 [7]

For solving system of equations, we can use either substitution where we plug one equation into the other, or elimination where we combine the equations.


- Using elimination, you would to eliminate one variable from both equations, so you automatically would get one equation with one variable!


- Using substitution means you are going to solve one equation for one variable and substitute with its value in the other equation in order to get also an equation with one variable.



Let's take an example ...

y+x=2            and      y-2x = 1

<span>Using <span>elimination, we need to subtract these two equation; one from the other...

y+x=2
-
y-2x=1
-----------
0+3x=1

then x=1/3       

and then substitute into any equation to get y-value</span></span>
y+x=2
y+1/3 = 2        >>>>>    y=5/3



NOW...<span>Using substitution
</span>y+x=2            and      y-2x = 1 >>(y=1+2x)

Plug (y=1+2x) into y+x=2    and solve for x
y+x=2
(1+2x) + x =2
1+3x = 2
3x=1

again (and for sure) x = 1/3

plug in x=1/3 into any of the equations above to get y:
y+x=2
y+1/3=2
y=5/3


DOne  !!!!!!


I hope you got the idea

If you still need help, just let me know.




7 0
4 years ago
How many packages of pencils should Phillip buy?
AfilCa [17]
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3 0
3 years ago
shirley is going to have the exterior of her home painted. tims painting charges  $250 plus $14 per hour. colorful prints charge
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6 0
3 years ago
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

Let me know if you need any clarifications, thanks!

~ Padoru

4 0
4 years ago
When a linear function has a slope of 5, what is the "run" part of the slope?
alukav5142 [94]
Slope equals rise over the run
so if slope = 5 then the rise also equals 5 and the run is 1


7 0
3 years ago
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