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2 years ago

7

Evaluate –32 + (2 – 6)(10)

2 answers:

pychu [463]2 years ago

8 0

Answer:

-72

Step-by-step explanation:

-32 + (2-6)(10)

-32 + (-4)(10)

-32 + -40

-72

joja [24]2 years ago

7 0

Answer:

-72

Step-by-step explanation:

Use PEMDAS and solve from left to right.

2 - 6 = -4

Parenthesis means multiplication.

-4 x 10 = -40

Then you add the negatives.

-32 + -40 or

-32 - 40 = -72

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3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

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Answer:

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Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

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$2x + 3(x + 2) = 2(x + 4) + 55$

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$= > 3x = 63 - 6 = 57$

$= > x = \frac{57}{3} = 19$

So, the consecutive odd integers are = 19 , 21 & 23.

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