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2 years ago

Use the quadratic formula to solve the quadratic equation x2 − 8x − 4 = 0.

1 answer:

4 0

Hello here is a solution :
x² − 8x − 4 = 0.
quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a x'= (-b+rot(d))/2a .......conrinu

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Solve using the lcd: 1/x = 1/5 + 5/4x

Black_prince [1.1K]

The value is x= -5/4

The least common denominator is the smallest number of all the common multiples of the denominators when 2 or more fractions are given.

Given:

1/x = 1/5+ 5/4x

1/x = 4x + 25 / 20x

20= 4x +25

4x= -5

x= -5/4

Learn more about this concept here:

brainly.com/question/2605216

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6 0

1 year ago

For which equation is y = 7 a solution?

Natasha2012 [34]

Answer:B

Step-by-step explanation:

y - 26 = -19

y + 26 - 26 = -19 + 26

y=7

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3 years ago

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How many ways can two students be chosen from a group of four? 4 6 14 10

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Answer:

Step-by-step explanation:

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2 years ago

Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 5 sin2 t, y = 5 cos2 t

rodikova [14]

$\begin{cases}x(t)=5\sin2t\\y(t)=5\cos2t\end{cases}\implies\begin{cases}\frac{\mathrm dx}{\mathrm dt}=10\cos2t\\\frac{\mathrm dy}{\mathrm dt}=-10\sin2t\end{cases}$

The distance traveled by the particle is given by the definite integral

$\displaystyle\int_C\mathrm dS=\int_0^{3\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt$

where $C$ is the path of the particle. The distance is then

$\displaystyle\int_0^{3\pi}\sqrt{100\cos^22t+100\sin^22t}\,\mathrm dt=10\int_0^{3\pi}\mathrm dt=30\pi$

6 0

2 years ago

Sorry i have another question what is the inequality of 8x−8≤−72.

vova2212 [387]

That answer is x≤−8

Inequality:

8x−8≤−72

Step number 1: You have to Add 8 to both sides.

8x−8+8≤−72+8

8x≤−64

Step number 2: You have to Divide both sides by 8.

8x /8 ≤ −64 / 8

Ur Answer:

x≤−8

Hope this helps :)

7 0

3 years ago

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