What are two ways friction can be increased
2 answers:
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Answer:
The graph with B(2,-3) i.e) y= x goes through the point M(-10,15).
Step-by-step explanation:
Consider M(-10,15) and given that equation is y = kx.
Now, substitute M(-10,15) in the equation
⇒ 15 = k × -10
⇒ k = =
⇒ y = x
Now, check with the given points B(2,-3) and B( , -2)
1) B(2,-3)
y = x
⇒(-3) = × 2
⇒ -3 = -3 ⇒ LHS = RHS
⇒ B(2,-3) is the required point.
2) for b( , -2)
LHS ≠ RHS.
So,The graph with B(2,-3) i.e) y= x goes through the point M(-10,15).
I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.
Now write the tangent ratios:
Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
Plug in what we know:
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.
Now write the tangent ratios:
Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
Plug in what we know: