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4 years ago

9

PLEASE ASSIST!! EXTRA POINTS PLUS BRAINLIEST ANSWER I’LL TRADE YOU MY MOM SHE MAKES RLLY GOOD COOKIES! Find the slope of the giv

en slide.

1 answer:

FinnZ [79.3K]4 years ago

8 0

Keep your mom, you only have one. But anyway;

Use the Pythagorean Theorem: A^2 + B^2 = C^2

12^2 + 21^2 = C^2

144 + 441 = C^2

585 = C^2

square root of 585 = approximately 24.2

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How could you represent 0.614 without<br> using hundredths?

jasenka [17]

Answer: You can either round to 0.6 or put in fraction form $\frac{307}{500}$

Step-by-step explanation:

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2 years ago

I NEED HELP ASAP PLS :(

kramer

It’s rectangular square

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3 years ago

A rectangular prism has a length of 18 feet, a height of 14 feet, and a width of 2 feet.

Semmy [17]

Answer:

504ft3

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3 years ago

Read 2 more answers

What is the value of c in the equation below? 2^-4(2^2)=a^b=c

Triss [41]

Answer:

The answer is option 4.

Step-by-step explanation:

You have to use Indices Law,

${a}^{m} \times {a}^{n} = {a}^{m + n}$

${a}^{ - n} = \frac{1}{ {a}^{n} }$

So for this question :

${2}^{ - 4} \times {2}^{2}$

$= {2}^{ - 4 + 2}$

$= {2}^{ - 2}$

${a}^{b} = c \\ c = {2}^{ - 2}$

$c = \frac{1}{ {2}^{2} }$

$c = \frac{1}{4}$

5 0

3 years ago

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

3 0

3 years ago