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damaskus [11]
3 years ago
9

PLEASE ASSIST!! EXTRA POINTS PLUS BRAINLIEST ANSWER I’LL TRADE YOU MY MOM SHE MAKES RLLY GOOD COOKIES! Find the slope of the giv

en slide.

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Keep your mom, you only have one. But anyway;

Use the Pythagorean Theorem: A^2 + B^2 = C^2

12^2 + 21^2 = C^2

144 + 441 = C^2

585 = C^2

square root of 585 = approximately 24.2

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A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choos
ss7ja [257]
<h3>Hello there i hope you are having a good day :) Your question : A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choose another letter A. What is the probability that both letters are A’s? Write your answer as a percent, with the percent symbol. If needed, round to the nearest tenth. </h3><h3>Firstly the word is SUMMER VACATION there are 14 letters in this word and 2 of them with the letter A So this would be 2/14 and 1/7 Then there is 13 letters because we used one already so it would be 1/13 Then the second A would equal 1/13 and this would be 1/7 and 1/13 you would times both given 1/91 now written that in percent with a percent symbol 1.0989011% So this would be 1.91%</h3><h3>Hopefully that helps you ❤</h3>

7 0
3 years ago
Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
alekssr [168]

Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

                       = mod (25-75+0-75) ÷ 2

                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

4 0
3 years ago
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
2 years ago
Help help help help please guys
maria [59]
I think the answer is 9
It's a smaller version of the other figure.
21/3=7
27/3=9
3 0
3 years ago
Someone thats good at geometry please help asap!
frosja888 [35]

Answer:

x=125

Step-by-step explanation:

∠PAT=180° - ∠ATP - ∠APT

∠PAT=180 - 3x - 3 -4x -4= (173 - 7x)°

3x + 3 + 4x + 4 + 173-7x = 180  

⇔x = 125

4 0
3 years ago
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