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3 years ago

Answer this question

Mathematics

1 answer:

kondor19780726 [428]3 years ago

3 0

24 is what i believe the answer is

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Find the perimeter of quadrilateral ABCD with vertices A=(1,1) B=(4,4) C=(7,1) D=(4,-2). Explain your answer.

Vanyuwa [196]

we have the coordinates of ABCD

there are 2 ways of doing this one is you find the distance of ab, bc, cd and da and then add the answers together. there is another way but i dont remember it properly so i am just gonna do it this way

distance between 2 point = $\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

$d = \sqrt {(4 - 1)^2 + (4 - 1)^2}$

$d = \sqrt {(3)^2 + (3)^2}$

$d = \sqrt {9 + 9}$

$d = \sqrt 18$

AB = 4.24

now repeat the same with all

BC= 4.24

CD= 4.24

DA= 4.24

so its a square with all the same sides so perimeter is 4 x 4.24

perimeter is 16.96

hope this helps

mark me as brainliest please

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2 years ago

Dave and ryan share some money in the ratio 7 : 4 . dave got $28, how much did ryan get?

Ronch [10]

Answer:

$16

Step-by-step explanation:

28/7=4

4*4=16

3 0

3 years ago

Read 2 more answers

An object consisting of two endpoints and all of the points between them

Over [174]

that'd be a segment.

⭕-------------------------------------⭕

3 0

3 years ago

What is the value of f(−3)?

Daniel [21]

Is that the whole question ?

7 0

3 years ago

National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke

NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

p2= 42/155= 0.2709

1) Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

<u>3) The z value is 2.05</u>

<u>4) Calculations:</u>

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994 ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

6 0

3 years ago