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Alik [6]
3 years ago
10

Please help and explain

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer: Option A

x=\frac{3+i}{2} or x=\frac{3-i}{2}

Step-by-step explanation:

Use the quadratic formula to find the zeros of the function.

For a function of the form

ax ^ 2 + bx + c = 0

The quadratic formula is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case the function is:

2x^2-6x+5=0

So

a=2\\b=-6\\c=5

Then using the quadratic formula we have that:

x=\frac{-(-6)\±\sqrt{(-6)^2-4(2)(5)}}{2(2)}

x=\frac{6\±\sqrt{36-40}}{4}

x=\frac{6\±\sqrt{-4}}{4}

Remember that \sqrt{-1}=i

x=\frac{6\±\sqrt{4}*\sqrt{-1}}{4}

x=\frac{6\±\sqrt{4}i}{4}

x=\frac{6\±2i}{4}

x=\frac{3\±i}{2}

x=\frac{3+i}{2} or x=\frac{3-i}{2}

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