A projectile is shot into the air following the path, h(x) = 3x 2 - 12x + 5. At what time, value of x, will it reach a maximum h
2 answers:
Answer:
Option B. x = 2
Step-by-step explanation:
A projectile is shot into the air following the path as h(x) = 3x² - 12x + 5
We have to find the value of x for which the height of the projectile is maximum.
Since projectile follows the path h(x) = 3x² - 12x + 5, a quadratic equation which means the path is in the form of a parabola.
Maximum height means vertex, which will be at the maximum height of the parabolic path.
Since x-coordinate of vertex of a parabola is represented by h =
From the given quadratic equation which is in the form of h(x) = ax² + bx + c
a = 3
b = -12
c = 5
Therefore, maximum height will be at x =
x = 2
Option B. x = 2 will be the answer.
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Answer:
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Step-by-step explanation:
The problem statement seems to presume you have seen an exponential function like this written as ...
f(t) = a0·(1 +r)^t
where a0 is the value corresponding to f(0) and "r" is the fractional rate at which the value increases for each increment of t.
Here, 1+r corresponds to 1.04 in the given function, so r = 0.04 = 4%. When the value is <em>greater than 0</em>, it means there is an <em>increase</em> by that fraction each time t increases by 1.
Here, t is not defined, either, but it would usually be used to represent years in a situation like this. (In other situations, it might represent months, hours, or millenia.)
Hence, the appropriate choice is the one that describes a 4% annual increase.
