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hichkok12 [17]
3 years ago
7

Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic

k require to build the wall? 102 × 6 106 610 10 × 62
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
The answer is 10 x 62. He has 62 across, and 10 vertically. To find how many total he needs, you have to multiply both together. I hope this helps!
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A class ring cost $260.00. Lewis has $80.00 in a saving account and earns $20.00 a week babysitting. Write an equation to repres
garri49 [273]
Pretty sure it’s (260-80) divided by 20
6 0
3 years ago
Read 2 more answers
8. What is the 10th term of the geometric sequence
kkurt [141]

Answer:

n=10

a10= - 3 (2)^(10-1)= -3(2)^9

= -1536

6 0
3 years ago
Which of the following pair of times has an elapsed time of 3 hours and 20 minutes between the times?
solniwko [45]

the answer is 3:20 to 6:00 which equals 3 hours and 20 minutes

7 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
What is the set fee, or initial value, of this function
Ber [7]
Answer:
The set fee would be $15

Explanation:
The set fee is the starting value. This means that it is the value of the y at x = 0 (y-intercept).

To get the set fee, we would first need to get the equation of the line.

Equation of the linear line has the following general formula:
y = mx + c
where m is the slope and c is the y-intercept

1- getting the slope:
we are given two points which are:
(20,25) and (50,40)
the slope = \frac{y2-y1}{x2-x1}=  \frac{40-25}{50-20} = 0.5

The equation now is:
y = 0.5x + c

2- getting the value of the y-intercept:
To get the value of the c, we will use any of the given points, substitute in the equation and solve for c.
I will choose the point (20,25)
y = 0.5x + c
25 = 0.5(20) + c
25 = 10 + c
c = 15

The equation of the line representing the scenario is:
y = 0.5x + 15

Now, we know that the value of the c is the y-intercept which is the initial value of the function at x=0.
In our situation, this represents the set fee.

Hope this helps :)
6 0
3 years ago
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