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Nady [450]
3 years ago
10

Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct

): 92, 70, 84, 87, 90, and 75.To compute your final course grade, the instructor decided to randomly select two exam scores, compute their mean, and use this score to dtermine your final course grade.
Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

Average of final course grade is 83.

Step-by-step explanation:

Given : Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct):

92, 70, 84, 87, 90, and 75.

To find : Compute their mean, and use this score to determine your final course grade ?

Solution :

Mean is defined as the total data divide by number of data.

M=\frac{\sum x_n}{n}

M=\frac{92+70+84+87+90+75}{6}

M=\frac{498}{6}

M=83

Therefore, Average of final course grade is 83.

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(2t-3)^3, can you help me?, please?
grandymaker [24]

Answer:

8t^3-36t^2+54t-27

Step-by-step explanation:

(2t-3)^3

(2t-3)(2t-3)(2t-3)

Multiply the first two terms

(4t^2 -6t -6t+9)(2t-3)

Combine like terms

( 4t^2 -12t +9) ( 2t-3)

Multiply

2t*( 4t^2 -12t +9) -3 ( 4t^2 -12t +9)

Distribute

8t^3 -24t^2 +18t-12t^2 +36t-27

Combine like terms

8t^3-36t^2+54t-27

6 0
3 years ago
Read 2 more answers
A peony plant with red petals was crossed with another plant having streaky petals. A geneticist states that 75% of the offsprin
Strike441 [17]

Answer:

The sample data confirm the geneticist's prediction that 75% of the offspring from this cross will have red flowers.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to test the claim made by the geneticist.

The hypothesis is defined as:

<em>H₀</em>: There is no difference between the observed and expected value,i.e. <em>p</em>₁ < 0.75.

<em>Hₐ</em>: There is a significant difference between the observed and expected value, i.e. <em>p</em>₁ > 0.75.

The test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}

Consider the tables attached below.

The value of the test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}=25.8133

The critical value is:

\chi^{2}_{\alpha, k-1}=\chi^{2}_{0.01, 1}=6.635

*Use a Chi-square table.

The critical region is:

\chi^{2}\geq 6.635

The test statistic value of 25.8133 lies in the critical region.

The null hypothesis is rejected at 1% level of significance.

<u>Conclusion</u>:

As the null hypothesis is rejected it can be concluded that 75% of the offspring from this cross will have red flowers.

7 0
3 years ago
Identify the parent function that can be used to graph the function f(x)=2[x-6]
zhannawk [14.2K]

Answer:

F(x) =2(1/2 x2-6x) +C

Step-by-step explanation:

Hope it helps

6 0
3 years ago
Plz help ASAP!! Explain your answer! I will mark at brainliest!!!
Rina8888 [55]

Answer:

A. 16.12 ft  B.  9.64 ft

Step-by-step explanation:

For both of these, you need Pythagorean's Theorem because we have right triangles.  In part A, we are given 2 legs and are asked to find the length of the hypotenuse:

14^2+8^2=PR^2 and

196+64=PR^2

and PR = 16.12 ft

In part B, we are given the length of the hypotenuse and side PQ remains the same:

14^2+QR^2=17^2 and

196+QR^2=289

QR^2=289-196 so

QR = 9.64 ft

3 0
3 years ago
I need help with both of these problems
GREYUIT [131]
The first question is D because if the
y-intercept is 1 then every point moves down three units.

The second question is J because a vertical line is not a function so it can’t be a linear function.
8 0
4 years ago
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