Answer:
8t^3-36t^2+54t-27
Step-by-step explanation:
(2t-3)^3
(2t-3)(2t-3)(2t-3)
Multiply the first two terms
(4t^2 -6t -6t+9)(2t-3)
Combine like terms
( 4t^2 -12t +9) ( 2t-3)
Multiply
2t*( 4t^2 -12t +9) -3 ( 4t^2 -12t +9)
Distribute
8t^3 -24t^2 +18t-12t^2 +36t-27
8t³ - 36t² + 54t - 27
(2t - 3)³
(2t - 3)(2t - 3)(2t - 3)
FOIL the first two binomials - first - outer - inner - last
(2t - 3)(2t - 3)
= 4t² - 6t - 6t + 9
= 4t² - 12t + 9
multiply this polynomial by the last binomial
(4t² - 12t + 9)(2t - 3)
distribute 2t
2t • 4t² = 8t³
2t • -12t = -24t²
2t • 9 = 18t
distribute -3
-3 • 4t² = -12t²
-3 • -12t = 36t
-3 • 9 = -27
combine
8t³ - 24t² + 18t - 12t² + 36t - 27
simplify
theres nothing here....
Hello,
answer B
x>=12
since x∈[12 ,+infinity)
