Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to
its resting place, the cheetah travels an average of 70 mph. If the cheetah traveled for 15 minutes, how many minutes did the return trip take to the nearest minute and second?
a. Set up the table as follows. Label the rows "To the River" and "From the River." Label the
columns "Distance," "Rate," and "Time (in Hours). Let t represent the unknown quantity in the
problem. Fill in the table.
b. From the table, set up an equation relating the distances.
c. Solve the problem. Write the answer in a complete sentence, stating it in terms of minutes and
seconds
a. Set up the table as follows. Label the rows "To the River" and "From the River." Label the
columns "Distance," "Rate," and "Time (in Hours). Let t represent the unknown quantity in the
problem. Fill in the table.
b. From the table, set up an equation relating the distances.
c. Solve the problem. Write the answer in a complete sentence, stating it in terms of minutes and
seconds
1 answer:
Answer:
The return trip take 5 minutes 27 seconds
Step-by-step explanation:
Let
x -----> the time it take the cheetah travels to go from its resting place to a rock near a river in hours
y ----> the time it take the cheetah the return trip to its resting place in hours
we know that
The distance from its resting place to a rock near a river is the same that the return trip
The average speed multiplied by the time is equal to distance
so
The total time is 15 minutes
Convert to hours
15 min=15/60 hours
x+y=(15/60)
x+y=1/4
4x+4y=1 -----> equation A
40x=70y ----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point ( 0.1591,0.0909)
see the attached figure
The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours
The time it take the cheetah the return trip to its resting place is 0.0909 hours
Convert to minutes and seconds
0.0909 hours=0.0909(60)=5.454 minutes
o.454 minutes=0.454(6)=27.24 seconds
therefore
The return trip take 5 minutes 27 seconds
<u><em>To the river</em></u>
The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours
The rate is 40 mph
To find out the distance multiply the average rate by the time
<em>Find out the distances</em>
The distance from its resting place to a rock near a river is
<u><em>From the river</em></u>
The time it take the cheetah the return trip to its resting place is 0.0909 hours
The rate is 70 mph
To find out the distance multiply the average rate by the time
<em>Find out the distances</em>
The distance of the return trip is
Both distances are the same
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Answer:
A. length = 23 cm; width = 5 cm
Step-by-step explanation:
So if 4 times the width would be and 3 more than would be
, the equation would be
. If the perimeter is 56, then the new equation,
can be formed. This simplifies to
, then to
, then to
, and finally,
. So the width is 5, and now plug it into the first equation.
, becomes
, becomes
.
So the dimensions are: length = 23 cm, width = 5 cm.
*And just to be sure, which is correct.