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Lostsunrise [7]
4 years ago
7

Plz help! 20 points!

Mathematics
1 answer:
Colt1911 [192]4 years ago
5 0
7. increasing; non-linear
8.A. y=4^x
9.A. y=6x
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The probability distribution for a
Katyanochek1 [597]
<h3>Answer:  0.17</h3>

This is the probability that corresponds to x = -5, which is less than x = -3, and it's the only x value of the list smaller than -3. There's not much else to say about this.

If we wanted to find something like P(X < -2), then we would add up the probabilities for x = -5 and x = -3 to get 0.17+0.13 = 0.30

7 0
4 years ago
Select all of the following that are ordered pairs of the given function.
Tatiana [17]
F(x) is the same as y.......so basically ur subbing in ur points into the equation to see if it comes out equal.

f(x) = 3 - 2x.....(-2,-1)....x = -2 and f(x) = -1
-1 = 3 - 2(-1)
-1 = 3 + 2
-1 = 5.....this is not true, so it is not a solution

and that is how to do this problem.....

(-1,5)......this IS a solution
(0,3)......this IS a solution
(1,0)...this IS NOT a solution
(2,-1)...this IS a solution

8 0
4 years ago
√81r⁶s⁴ simplified and kept in radical form​
ahrayia [7]

Answer:

its A

Step-by-step explanation:

i did the test

6 0
3 years ago
How Does Each Expression Represent the number of small squares in the figure
krek1111 [17]
Can you provide a picture so I can help you?
4 0
4 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
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