Based on the diagram and the ratio of width and height in it, the width that Mr. Howell should make his table is 48 inches .
<h3>How wide should Mr. Howell's table be?</h3>
The width of the table in the diagram is 12 cm and the height is 6cm.
This means that the ratio of width to height is:
12 : 6
2 : 1
As Mr. Howell wants his table to be 24 inches high, the width of the table would be:
2 : 1
x : 24
Cross-multiply to get:
x = 48 inches
Find out more on ratios at brainly.com/question/20594266
#SPJ1
Answer:
I would say just take the big number and subtract the 41??...
Answer:
The polynomial f(x) = x^2 - 8x - 20
Answer:
$11.5
Step-by-step explanation:
Add all of them together
Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54