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Tasya [4]
3 years ago
5

A club has 12 members. In how many ways can we select four members to go on a trip?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0
This is the number of combinations of 4 from 12

12C4   =        12!
                 ----------
                  4! 8!

=    12*11*10*9             11*5*9  =  495
      --------------     = 
        4*3*2*1
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Simplify to create an equivalent expression<br><br> 6(5r-11)-(5-r)
dolphi86 [110]

Answer:

B or 31r-71

Step-by-step explanation:

First, use distributive property to expand the first term.

30r-66-(5-r)

Remove the parenthesis of the third term:

30r-66-5+r

Combine like terms

31r-71

7 0
4 years ago
Simplify.
riadik2000 [5.3K]
I think the answer would be c
4 0
3 years ago
6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0
3 years ago
Look how he has proved that
Advocard [28]

Answer:

false

Step-by-step explanation:

as a guy who studied calculus, a lot of things were done that are just mathematically incorrect. for instance,

infinity - infinity is not 0.

0÷0 is undefined. so you cant just equate it to ( 2 × infinity)

to sum up this proof is entirely false.

if you still have any doubts make sure to ask.

5 0
3 years ago
Read 2 more answers
Here’s the answer you need to know
vovikov84 [41]
Thank you sooo much Maddi441
8 0
3 years ago
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