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11Alexandr11 [23.1K]
3 years ago
11

Please help (if you can)

Mathematics
1 answer:
jasenka [17]3 years ago
8 0
Hghgghfngg 1 5 and e
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The daily sales at a convenience store produce a normal distribution with a mean of $1,250 and a standard deviation of $125. The
timama [110]

Answer:

0.6844 is the required probability.        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $1,250

Standard Deviation, σ = $125

We are given that the distribution of daily sales is a bell like shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find

P(sales less than $1,310)

P( x < 1310) = P( z < \displaystyle\frac{1310 - 1250}{125}) = P(z < 0.48)

Calculation the value from standard normal z table, we have,  

P(x < 1310) =0.6844= 68.44\%

0.6844 is the probability that sales on a given day at this store are less than $1,310.

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3 years ago
How to predict the charge of monatomic ions.
FromTheMoon [43]

Answer:

by gaining or losing electrons

Step-by-step explanation:

hope it helped

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6 0
2 years ago
Simplify 10x-4-2x+19
borishaifa [10]
8x - 23 because you answer them until you have it all simplified
7 0
3 years ago
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mr Goodwill [35]

Answer:

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Step-by-step explanation:

6 0
3 years ago
2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe
k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and  Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

N=(25+60)+(40+60) - 60\\N= 125

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%

3 0
3 years ago
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