The number 2+√3 is irrational ,it cannot be expressed as a ratio of integers a and b. To prove that this statement is true, let us Assume that it is rational and then prove it isn't (Contradiction).
So the Assumptions states that :
(1) 2+√3
Where a and b are 2 integers
Now since we want to disapprove our assumption in order to get our desired result, we must show that there are no such two integers.
Squaring both sides give :
3=a/b
3=a^2/ b^2
what two number time itself (twice) can be divide by another number time itself (twice) to get 3
Answer:
2/3
8/12
Step-by-step explanation:
You just divide each numerator 4 (5÷4) and each denominator by 6 (8÷6) and see if the numbers are the same.
5÷4=1.25
8÷6=1.33
They are not equivalent, so 5/8 is not correct
2÷4=0.5
3÷6=0.5
They are equivalent, so 2/3 is correct
<u>Please</u><u> give</u><u> brainliest</u><u> if</u><u> I</u><u> helped</u><u>!</u><u> </u><u>:</u><u>)</u>
Answer: Squares to circles 8:6or 2:3
Circles to squares 6:8 or 3:2
18 circles
Step-by-step explanation:
Answer:
(-6, -5).
Step-by-step explanation:
If there is a zero between the integers there will be a change of sign of f(x).
x^3 + 5x^2 - x - 6
f(1) = 1 + 5 - 1 - 6 = -1
f(-1) = -1 + 5 + 1 - 6 = -1
f(2) = 8 + 20 - 2 -6 = 20
There' a change of sign between f(1) and f(2) so there is a zero between (1, 2).
f(-2) = -8 + 20 + 2 - 6= 6
So there is also a zero between -1 and -2. (-2, -1)
F(-4) = 14, f(-5) = -1 = change of sign so there is also a zero in (-5,-4)
f(-6) = -36 - no change in sign between -5 and -6.
Narrowing it down it's either a or c because the other 2 choices open downward (negative a).
Graphing the 2 parabolas choice c is narrower.
c
