Question

What is the surface area of the regular pyramid given below?

Answer 1

For this case we have by definition, that the total surface area of a regular pyramid with a square base is given by:

$SA = \frac {1} {2} p * S + A_ {b}$

Where:

p: It is the perimeter of the base

S: It's the inclination

$A_ {b}:$ It is the area of the base

Substituting:

$A_ {b} = 7 ^ 2 = 49units ^ 2\\p = 7 + 7 + 7 + 7 = 28units\\S = 10units\\SA = \frac {1} {2} 28 * 10 + 49\\SA = 140 + 49\\SA = 189 \ units ^ 2$

ANswer:

Option B