Given that there were 30 bacteria present originally.
a=30
Also given that the number doubles every one hour.
After one hour the count =2×30=60
Since the count doubles every hour it forms a G.P. with r=2
a,ar,ar2........
The count at the end of 2nd hour=ar^2=30×2^2=120
The count at the end of 4th hour=ar^4=30×2^4=480
The count at the end of 8th hour=ar^8n=30×2^8=7680
etc.
The count at the end of n^th hour=ar^n=30×2^n
Also, the equation y=30*(2)^8/1 give the same result y= 7680
Answer:
{19,13,7,1}
Step-by-step explanation:
Since the domain is the input we have to plug in each of those numbers to get the range ( or the output.) When we plug in -4 we get 19. When we plug in -2 we get 13, when we plug in 0 we get 7 and when we plug in 2 we get 1. (:
Answer:
0.09
Step-by-step explanation:
Given :
P(bike) = 0.8
P(car) = 0.2
P(Late given car) = P(Late | car) = 0.05
P(Late given bike) = p(Late | bike) = 0.1
Probability that professor is late :
P(late) = [P(Late | car) * p(car)] + [p(Late | bike) * p(bike)]
P(late) = [0.05 * 0.2] + [0.1 * 0.8]
P(late) = 0.01 + 0.08
P(late) = 0.09
Answer:
i will see if i can figure it out
gl dude
Step-by-step explanation:
