To find the original price, you could use a variable to represent the original price in this equation;
Let p represent the original price
.70 × p=11.20
to solve this, we'd isolate the variable (p)
p=11.20 ÷.70
p=16
The original price was $16
Answer:
3s + 3t
Step-by-step explanation:
To simplify this expression, all you need to do is distribute the 3, which means you basically multiply whatever is in the parentheses by 3:
(s + t) * 3 =
3s + 3t
And that is the simplified form for this expression.
Hope this helps :)
Answer:
The mean is: 85
Step-by-step explanation:
First you need to add everything up :
1 * 2 = 2
2 * 1 = 2
3 * 3 = 9
4 * 5 = 20
5 * 4 = 20
6 * 3 = 18
7 * 2 = 14
(I multiplyed them all first because i was fast than doing 4+4+4+4+4 because its the same as 4 * 5)
then add them all up 2+2+9+20+20+18+14=85
Answer:
The median is: 4
Step-by-step explanation:
Get the data in NUMERICAL ORDER (smallest to largest), then eliminate the extremes until we're at the middle. (basically chopping off the end till you get to the middle) Therfore The answer would be 4.
Answer:
The mode would be: 4
Step-by-step explanation:
The mode is Get the data in NUMERICAL ORDER, and see which value is the most frequent (we can have more than one mode).
Answer:
25%
Step-by-step explanation:
firs you do 5 divided by 20 because there are 20 x's. this will = 0.25
0.25 = 25%
I hope I get brainiest. Sorry for taking forever. Have a nice day!
37 is a whole number , interger and rational number
Answer:
39 is the 13th term
Step-by-step explanation:
Okay so essentially the 
is just a substitute for x.
See how in the equation they put n into the x spot:
They changed the variable names:
Now we know what the n actually means, plus when they ask about the terms youre trying to find it's based off of that n:
When they say, 13 term, they mean 
which would be the 13th answer in the series. So the first term would be based off of 
So whatever number is in the n position by a is what you'll be plugging into the x spot.
These are all the answers leading up to the 13th term they asked for, and you can continue thus same equation with whatever number you can put into the n space.
