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3 years ago

I still cant figure it out . ughh −2∣5w−7∣+9=−7

Mathematics

2 answers:

Fofino [41]3 years ago

3 0

W=3,-1/5 is the answer

Leviafan [203]3 years ago

3 0

Subtract 9 from both sides
Divide by -2
Split absolute value into 5w+7 and 5w-7
Then solve for w
There are 2 answers

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Minneapolis, Minnesota and Portland, Oregon have very similar latitudes. (Latitude measures how far north or south a place is, w

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Answer:

Step-by-step explanation:

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3 years ago

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Are 12/7 and 36/21 proportional

anastassius [24]

Answer:

Step-by-step explanation:

Cross multiply:

12 * 21 = 7 * 36

Simplifying

12 * 21 = 7 * 36

Multiply 12 * 21

252 = 7 * 36

Multiply 7 * 36

252 = 252

Add '-252' to each side of the equation.

252 + -252 = 252 + -252

Combine like terms: 252 + -252 = 0

0 = 252 + -252

Combine like terms: 252 + -252 = 0

0 = 0

Solving

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3 years ago

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(84x - 69y) - (65x + 34y)

Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

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19x -103y

6 0

3 years ago

Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20 Find: BC AD

alexdok [17]

Answer:

 BC = 10 and AD = 30

Step-by-step explanation:

In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.

Since, line AD is sum of AK and KD, then

AD = AK + KD

AD = 10 + 20

AD = 30

Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD

so, BC = KL and AK = LD

KL = AD - LD

KL = 20 - 10

KL = 10

Since, BC = KL then BC = 10

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3 years ago

10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

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