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2 years ago

Subtracting a negative number gives the same answer as adding that number.

Mathematics

2 answers:

vazorg [7]2 years ago

6 0

It would be 7 because 16-7=23 if that helps

Lady bird [3.3K]2 years ago

5 0

The correct answer is 7

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Annabelle the ant and Archibald the ant are on a large coordinate grid. Annabelle is at (3,4) and Archibald is at (33,44). If bo

kvasek [131]

<u>Part a)</u> If both ants skate directly towards each other, starting at the same time and skating the same speed, what will be the coordinates of their meeting place?

Let

A(3,4) B(33.44)

we know that

If both ants skate directly towards each other, starting at the same time and skating the same speed

then

the coordinates of their meeting place is the midpoint AB

<u>Find the midpoint AB</u>

in the x-coordinate

(3+33)/2=18

in the y-coordinate

(4+44)/2=24

the midpoint AB is (18,24)

therefore

<u>the answer Part a) is </u>

the coordinates of their meeting place is (18,24)

<u>Part b)</u> How far will each ant skate?

<u>Find the distance AB</u>

$d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

substitute the values

$dAB=\sqrt{(33-3)^{2}+(44-4)^{2}}$

$dAB=\sqrt{2,500}$ units

$dAB=50$ units

<u>Find the half distance AB</u>

50/2=25 units

therefore

<u>the answer part b) is</u>

Each ant will skate 25 units

7 0

3 years ago

A rectangular pool is 10 meters wide and 16 meters long.What is the area of the pool? What is asked?What are given?What is/are t

Morgarella [4.7K]

<h3>Answer:</h3>

A=160 m

<h3>Solution:</h3>

The formula for the Area of a rectangle is:
A=LW
In the above formula, L stands for the length and W stands for the width.
We are given:
L=16 m
W=10 m
We are asked to find the area of the rectangular pool.
The operation that we're going to use here is:
Multiplication.
Multiply:
A=16*10
A=160 m

Hope it helps.

Do comment if you have any query.

7 0

2 years ago

Read 2 more answers

Please help solve by elimination I hope its not blurry Have a nice day and Goodnight

strojnjashka [21]

Answer:

$\displaystyle \textcolor{black}{4.}\:[-3, -5]$

$\displaystyle \textcolor{black}{3.}\:[8, -1]$

$\displaystyle \textcolor{black}{2.}\:[4, -7]$

$\displaystyle \textcolor{black}{1.}\:[3, -2]$

Step-by-step explanation:

When using the Elimination method, you eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-5x - 3y = 30}} \right.$

{2x - 3y = 9

{⅖[−5x - 3y = 30]

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-2x - 1\frac{1}{5}y = 12}} \right. \\ \\ \frac{-4\frac{1}{5}y}{-4\frac{1}{5}} = \frac{21}{-4\frac{1}{5}} \\ \\ \boxed{y = -5, x = -3}$

------------------------------------------------------------------------------------------

$\displaystyle \left \{ {{x - 2y = 10} \atop {x + 3y = 5}} \right.$

{x - 2y = 10

{⅔[x + 3y = 5]

$\displaystyle \left \{ {{x - 2y = 10} \atop {\frac{2}{3}x + 2y = 3\frac{1}{3}}} \right. \\ \\ \frac{1\frac{2}{3}x}{1\frac{2}{3}} = \frac{13\frac{1}{3}}{1\frac{2}{3}} \\ \\ \boxed{x = 8, y = -1}$

_______________________________________________

$\displaystyle \left \{ {{y = -3x + 5} \atop {y = -8x + 25}} \right.$

{y = −3x + 5

{−⅜[y = −8x + 25]

$\displaystyle \left \{ {{y = -3x + 5} \atop {-\frac{3}{8}y = 3x - 9\frac{3}{8}}} \right. \\ \\ \frac{\frac{5}{8}y}{\frac{5}{8}} = \frac{-4\frac{3}{8}}{\frac{5}{8}} \\ \\ \boxed{y = -7, x = 4}$

------------------------------------------------------------------------------------------

$\displaystyle \left \{ {{y = -x + 1} \atop {y = 4x - 14}} \right.$

{y = −x + 1

{¼[y = 4x - 14]

$\displaystyle \left \{ {{y = -x + 1} \atop {\frac{1}{4}y = x - 3\frac{1}{2}}} \right. \\ \\ \frac{1\frac{1}{4}y}{1\frac{1}{4}} = \frac{-2\frac{1}{2}}{1\frac{1}{4}} \\ \\ \boxed{y = -2, x = 3}$